Question

(4x-34)²-(2x+4)*(3x-54)


Пожалуйста, помогите!

Answer 1

(4x-34)²-(2x+4)*(3x-54) =16x²-272x+1156-6x²-12x+108x+216=10x²-176x+1372

Answer 2

$(4x - 34) {}^{2} - (2x + 4) times (3x - 54) \ \ = 16 {x}^{2} - 272x + 1156 - (6 {x}^{2} - 108x + 12x - 216) \ \ = 16 {x}^{2} - 272x + 1156 - (6 {x}^{2} - 96x - 216) \ \ = 16 {x}^{2} - 272x + 1156 - 6 {x}^{2} + 96x + 216 \ \ = 10 {x}^{2} - 176x + 1372$