Question

Решите неравенство 3х^2+2х-1 больше 0

Answer 1

$3x^2+2x-1 > 0 \ D=4+12=16 \ x_1=frac{-2-4}{6}=-1 \ x_2=frac{-2+4}{6}=frac{1}{3} \ 3(x+1)(x-frac{1}{3}) > 0$

---(+)--(○-1)--(-)----(○1/3)----(+)--->

$x in (-infty;-1)cup (frac{1}{3};+infty)$