Question

Нужна помощь, 2 вариант 1-3 задания.

Answer 1

2−1−3⋅2+7⋅2+1=92
2x−1−3⋅2x+7⋅2x+1=92
(1−3⋅2+7⋅22)⋅2−1=92
(1−3⋅2+7⋅22)⋅2x−1=92
(1−6+7⋅4)⋅2−1=92
(1−6+7⋅4)⋅2x−1=92
(1−6+28)⋅2−1=92
(1−6+28)⋅2x−1=92
23⋅2−1=92
23⋅2x−1=92
2−1=4
2x−1=4
2−1=22
2x−1=22
−1=2
x−1=2
=2+1
x=2+1
=3