Question

найдите корень уравнения √4+x+√x=4

Answer 1

$sqrt{4+x} + sqrt{x} = 4\ x geq 0\ 4 + x + 2sqrt{x^2+4x} +x = 16 \ 2sqrt{x^2+4x} = -2x + 12 \ sqrt{x^2+4x}= 6-x \ x^2 + 4x = 36 - 12x + x^2 \ 16x = 36 \ x = 2,25$