Question

Срочно!!Пожалуйста, 40б

Answer 1

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Answer 2

$f(x) = frac{ x^{3} }{3} -5 x^{2} +28x-7\\f'(x)= x^{2} -10x+28\\f'( x_{0})= x_{0} ^{2}-10 x_{0}+28\\ x_{0} ^{2} } -10 x_{0}+28=3\\ x_{0} ^{2}-10 x_{0}+25=0\\( x_{0}-5) ^{2} =0\\ x_{0}-5=0\\ x_{0} =5$


$y_{0}= frac{ 5^{3} }{3}-5*5 ^{2} +28*5-7= frac{125}{3} -125+140-7=41 frac{2}{3} +8=49,6$

Ответ: (5 , 49,6)

Answer 3

2/3 при округлении =0.7