Question

2arcsin1+arccos(-√2/2)-3arctg(-1)

Answer 1

$text{arcsin 1} = frac{pi}{2}$

$text{arccos}( -frac{sqrt 2}{2} ) = pi - text{arrcos}frac{sqrt2}{2} = pi - frac{pi}{4} = frac{3pi}{4}$

$text{arctg(-1)} = -text{arctg1} = -frac{pi}{4}$

$2cdot text{arcsin 1} +text{arccos}( -frac{sqrt 2}{2} ) - 3cdottext{arctg(-1)} = 2cdotfrac{pi}{2}+frac{3pi}{4}+frac{3pi}{4} = frac{5pi}{2} = 2,5pi$