Question

Найдите корень уравнения 16^9-2х =(1/4)^х

Answer 1

$16^{9-2x}=frac{1}{4}^x \ 4^{18-4x}=4^{-x} \ 18-4x=-x \ 3x=18 \ x=6$

Answer 2

$1 {6}^{9 - 2x} = ( frac{1}{4} ) {}^{x} \ \ {2}^{36 - 8x} = {2}^{ - 2x} \ \ 36 - 8x = - 2x \ \ - 8x + 2x = - 36 \ \ - 6x = - 36 \ \ x = 6$