Question

Сократить дробь:

4c²-25d²
____________
4c²+20cd+25d²

Answer 1

(4c²-25d²)/(4c²+20cd+25d²)=(2c+5d)(2c-5d)/(2c+5d)(2c+5d)=
=(2c-5d)/(2c+5d)


A²-B²=(A+B((A-B), A²+2AB+B²=(A+B)(A+B)

Answer 2

4c²-25d² (2c-5d)-(2c+5d)- 2c-5d
____________=____________ =_____
4c²+20cd+25d² (2c+5d)-²- 2c+5d