Question

Помогите решить:
Iog((5-х)в квадрате)=2

Answer 1

$log (5-x)^2 = 2log|5-x| = 2 Rightarrow log |5-x| = 1 Rightarrow |5-x| =$$10^{log|5-x|} = 10^1 = 10 Rightarrow |5-x| = 10 Rightarrow x = -5, x = 15$
Ответ: x = -5, x = 15.