Question

Помогите пожалуйста, срочно решить
(1-3i)(1+3i)-2
(2-i)^2 + i(3i-4)
i^16+2i6

Answer 1

1).
$(1 - 3i)(1 + 3i) - 2 = \ 1 - 9 {i}^{2} - 2 = \ = - 1 - 9 {i}^{2}$
2)

${(2 - i)}^{2} + i(3i - 4) = \ = 4 - {i}^{2} + 3 {i}^{2} - 4i = \ = 4 - 4i + 2 {i}^{2}$
3) не знаю.