Question

6sin150°cos150°/cos^2 30°- sin30°
пожалуйста решите...

Answer 1

$frac{6sin150^0cos150^0}{cos^230^0-sin30^0}= frac{6sin(180^0-30^0)cos(180^0-30^0)}{ (frac{ sqrt{3} }{2})^2 - frac{1}{2} } = frac{6* sin30^0*(-cos30^0) }{ frac{3}{4} - frac{2}{4} } =$$frac{6* frac{1}{2}* frac{- sqrt{3} }{2} }{ frac{1}{4} }=- frac{6 sqrt{3} *4}{1*4}=-6 sqrt{3}$