Question

упростить ((1+2〖sin〗^2 x)/(sin⁡x+cos⁡x ))-sin⁡x

Answer 1

$displaystyle frac{1+2sin^2x}{sin x+cos x}-sin x= frac{1+2sin^2x-sin x(sin x+cos x)}{sin x+cos x} =\ \ \ = frac{1+2sin^2x-sin^2x-sin xcos x}{sin x+cos x}= frac{1+sin^2x-sin xcos x}{sin x+cos x}$