Question

Помогите решить (задание внутри)

Answer 1

1. (20x + 3x² - 6x³ - x⁴)' = 20 + 6x - 18x² - 4x³
2. (arcsinx - √x)' = 1/√(1-x²) - 1/(2√x)
3. (√ln(x² - x))' = 1/(2√ln(x²-x) * 1/(x²-x) * (2x-1) = (2x-1)/(2(x²-x)√ln(x²-x))