Question

Вычислите: f'(π|2), если f(x) =xsinx помогите экзамены срочно

Answer 1

f'(x) = (x)'*sinx+x*(sinx)' =sinx+x*cosx
f'(p/2)= sin(p/2)+p/2*cos(p/2) = 1+р/2*0=1

Answer 2

f'(x)=x'*sinx+x*(sinx)'=sinx+x*cosx ; f'(π/2)=sin(π/2)+(π/2)*cos(π/2)=1