Question

ctg 4п/3 - 3tg2п －sin п/3 вычислите

Answer 1

ctg(4π/3)=ctg(π+π/3)= -ctg(π/3)= -√3/3
tg2π=0
sin(π/3)=√3/2
Получаем
-√3/3-3*0-√3/2=(-2√3)/6-(3√3)/6=(-5√3)/6