Question

(2√2)^-2+(√3/3)^-4+√7+2√6×√7-2√6

Answer 1

По действиям

(2√2)^(-2) = 1 / (2√2)^2 = 1 / (4*2) = 1/8

(√3/3)^(-4) = (1/√3)^(-4) = (√3)^4 = 3^2 = 9

√(7+2√6)*√(7-2√6) = √[(7+2√6)(7-2√6)] = √(49-4*6) = √(49-24) = √25 = 5

Складываем

1/8 + 9 + 5 = 14 1/8 = 14,125