Question

решите пожалуйста....

Answer 1

$1) lim_{x to infty} frac{2x^3+3x^2-5}{x^3+1} = lim_{x to infty} frac{2+frac{3}{x}-frac{5}{x^3}}{1+frac{1}{x^3}} =2$

$2) lim_{x to 3} frac{3-x}{(x-3)(x+3)} = lim_{x to 3} frac{-1}{x+3}=-frac{1}{6}$

Answer 2

спасибо<3

Answer 3

б) lim ( 3-x) / ( 3 -x)( -3 -x) = lim 1 / ( -x -3 ) = -1/6
a) lim (2 + 3/x - 5/ x^3) / ( 1 + 1/x^3) = 2/1 =2