Question

Помогите с решением.......................

Answer 1

Решение на фотографии

Answer 2

множили 10 на 0,01 и получили 0,01

Answer 3

Описка, конечно, 0,1

Answer 4

$frac{ frac{1}{a} - frac{1}{b + c} }{ frac{1}{a} + frac{1}{b + c} } times (1 + frac{ {b}^{2} + {c}^{2} - {a}^{2} }{2bc} ) div frac{a - b - c}{abc} = \ = frac{ frac{b + c - a}{a(b + c)} }{ frac{b + c + a}{a(b + c)} } times frac{2bc + {b}^{2} + {c}^{2} - {a}^{2} }{2bc} times frac{abc}{a - b - c} = \ = frac{b + c - a}{a(b + c)} times frac{a(b + c)}{b + c + a} times frac{( {b}^{2} + 2bc + {c}^{2}) - {a}^{2} }{2} times frac{a}{a - b - c} = \ = frac{b + c - a}{b + c + a} times frac{(b + c)^{2} - {a}^{2} }{2} times frac{a}{a - b - c} = \ = frac{b + c - a}{b + c + a} times frac{(b + c - a )(b + c + a)}{2} times frac{a}{a - b - c} = \ = frac{b + c - a}{1} times frac{b + c - a }{2} times frac{a}{ - ( - a + b + c)} = \ = frac{ {(b + c - a)}^{2} }{ 2} times frac{a}{ - (b + c - a)} = \ = frac{a(b + c - a)}{ - 2}$
a=0,02
b=-11,05
c=1,07
$frac{a(b + c - a)}{ - 2} = \ = frac{0.02(-11.05 + 1.07 - 0.02)}{ - 2} = \ = frac{0.02 times (-10)}{ - 2} = 0.01 times 10 = \ = 0.1$