Question

Помогите
lg(2x-1)=3(lg4-lg2)

Answer 1

$lg(2x-1)=3(lg4-lg2)$
$lg(2x-1)=3(lg( frac{4}{2}) )$
$lg(2x-1)=3lg2$
${10}^{3lg2} = 2x - 1$
${10}^{lg {2}^{3} } = 2x - 1$
${2}^{3} = 2x - 1$
$8 = 2x - 1$
$2x = 9$
$x = 4.5$