Question

Тест по математике, плииииз

Answer 1

3)
${ sin(x) }^{2} + 5 sin(x )= - 4 \ { sin(x) }^{2} + 5 sin(x) + 4 = 0 \ sin(x) = t \ {t}^{2} + 5t + 4 = 0 \ d = 25 - 16 = 9 \ x 1= - 1 \ x2 = - 4$