Question

2sin^2x-2sincosx=0 помогите

Answer 1

$2sin ^{2}x - 2sin cos x = 0 / : cos ^{2}x ne 0 \ \ 2mathrm{tg}^{2} x - 2mathrm{tg}x = 0 \ \ 2mathrm{tg}x (mathrm{tg}x - 1) = 0 \ \ left[ begin{gathered} 2mathrm{tg}x = 0 \ mathrm{tg}x - 1 =0 \ end{gathered} right. ; left[ begin{gathered} x = pi n, n in Z \ x = pm dfrac{pi}{4} + 2pi k, k in Z \ end{gathered} right.$

Ответ: x = πn, n ∈ Z ; x = π/4 + πk, k ∈ Z