Question

решите уравнение.....:

Answer 1

$log_{2} x = t$

t^2 -5t -6 = 0

D = 25+24 = 49

t1 = (5 + 7)/2 = 6

t2 = (5-7)/2 = -1

$log_{2} x = -1$

x1 = 1/2

$log_{2} x = 6$

x2 = 2^6 = 64