Question

Срочно помогите решить

Answer 1

7)

х ∈ (-(π+arcsin√2/2)+2πn; arcsin√2/2+2πn)

x ∈ ( -(π+π/4)+2πn; π/4+2πn)

x ∈( -5π/4+2πn; π/4+2πn)

8)

=⁴√(6-√20)(6+√20) = ⁴√(36-20) = ⁴√16 = |2|

9)

= 3²- 3³+2⁴ - 2² = 9-27+16-4 = -18+12 = -6

10)

х²-4х+3≤0

(х-1)(х-3)≤0

х∈[1;3]