Question

y=3x^2+4 ,x=-3,x=2,осьОx. Найти Sф

Answer 1

S = $intlimits^{2}_{-3} {(3x^{2}+4-0)} , dx = (3frac{x^{3}}{3} + 4x) |_{-3} ^{2} = (x^{3} +4x)|_{-3}^{2} = 2^{3} - (-3)^{3} + 4*2 - 4*(-3) =55$