Question

ПОМОГИТЕ ПОЖАЛУЙСТА

Answer 1

2)
$frac{5x}{4} - x + 1 = ( 3 - x) frac{1}{2} \ frac{5x}{4} - x + 1 = frac{3}{2} - frac{x}{2} \ frac{5x}{4} - x + frac{x}{2} = frac{3}{2} - 1 \ frac{5x}{4} - frac{4x}{4} + frac{2x}{4} = frac{3}{2} - frac{2}{2} \ frac{3x}{4} = frac{1}{2} \ 3x = 2 \ x = frac{2}{3}$
3)
$frac{3}{2} - ( frac{x}{4} + frac{1 - 2x}{6} ) = 2 \ frac{3}{2} - ( frac{x}{4} + frac{1}{6} - frac{x}{3} ) = 2 \ - frac{x}{4} + frac{x}{3} = 2 - frac{3}{2} + frac{1}{6} \ - frac{3x}{12} + frac{4x}{12} = frac{12}{6} - frac{9}{6} + frac{1}{6} \ frac{x}{12} = frac{4}{6} \ x = frac{12 times 4}{6} = 8$
4)
$frac{1}{7} times (5x - 1) - (2 + frac{x}{2} ) = 0 \ frac{5x}{7} - frac{1}{7} - 2 - frac{x}{2} = 0 \ frac{5x}{7} - frac{x}{2} = frac{1}{7} + 2 \ frac{10x}{14} - frac{7x}{14} = frac{1}{7} + frac{14}{7} \ frac{3x}{14} = frac{15}{7} \ 3x = frac{14 times 15}{7} = 30 \ x = 10$