Question

Срочно и с подробным решением

(3×10^2)^2×(7×10^-5)

(x-4)^2+(x+7)^2=2x^2-1

Answer 1

1) ${(3 times {10}^{2} )}^{2} times (7 times {10}^{ - 5} ) = 9 times {10}^{4} times 7 times {10}^{ - 5} = frac{63}{10} = 6.3$

2) ${(x - 4)}^{2} + {(x + 7)}^{2} = 2 {x}^{2} - 1 \ {x}^{2} - 8x + 16 + {x}^{2} + 14x + 49 - 2 {x}^{2} + 1 = 0 \ 6x = - 66 \ x = - 11$

Answer 2

$1)(3*10^2)^2*(7*10^{-5} )=9*10^4*frac{7}{100000} =frac{9*7}{10} =frac{63}{10}=6,3\2)(x-4)^2+(x+7)^2=2x^2-1\x^2-8x+16+x^2+14x+49= 2x^2-1\ 2x^2+6x+65=2x^2-1\ 6x+66=0\ x=frac{-66}{6}=-11$