Question

Варианты ответов:
А)4
B)0
C)4^2n
D)2^n-1

Answer 1

20*2^(4n-5)-80*(4^(n-2))^2=
=20*2^(4n-5)-80*2^(4n-8)=
=20*2^(4n-5)-10*2^(4n-5)=
=10*2^(4n-5)=5*2^(4n-4)=5*4^(2n-1)

Answer 2

20*2⁴ⁿ⁻⁵-80*(4ⁿ⁻²)²=

=20*2⁴ⁿ⁻⁵-80*4⁽ⁿ⁻²⁾²=

=20*2⁴ⁿ⁻⁵-80*4²ⁿ⁻⁴=

=20*2⁴ⁿ⁻⁵-80*2⁴ⁿ⁻⁸=

=(20*2³-80)*2⁴ⁿ⁻⁸=

=(20*8-80)*2⁴ⁿ⁻⁸=

=(160-80)*2⁴ⁿ⁻⁸=

=80*2⁴ⁿ⁻⁸