Question

Помогите решить,если можно с объяснением

Answer 1

1)
${(2x + 4)}^{2} = {(3x - 8)}^{2} \ |2x + 4| = |3x - 8| \ 2x + 4 = 3x - 8 \ - x = - 12 \ x = 12 \ 2x + 4 = - 3x + 8 \ 5x = 4 \ x = frac{4}{5}$
2)
${(6x + 2)}^{2} =( 3x - 2)^{2} \ |6x + 2| = |3x - 2 | \ 6x + 2 = 3x - 2 \ 3x = - 4 \ x = - frac{4}{3} \ 6x + 2 = - 3x + 2 \ 9x = 0 \ x = 0$
3)
$( {7x}^{2} + 8) {}^{2} = {(7x + 7)}^{2} \ 7x {}^{2} + 8 = |7x + 7| \ a)7x + 7 geqslant 0 \ x geqslant - 1 \ 7x {}^{2} + 8 = 7x + 7 \ 7 {x}^{2} - 7x + 1 = 0 \ d = 49 - 28 = 21 = sqrt{21} \ x = frac{7 + sqrt{21} }{14} \ x = frac{7 - sqrt{21} }{14} \ b)7x + 7 < 0 \ x < - 1 \7 {x}^{2} + 8 = - 7x - 7 \ 7 {x}^{2} + 7x + 15 = 0 \ d = 49 - 4 times 7 times 15 = 49 - 420 \ d < 0$
4)
$(2 {x}^{2} + 2) {}^{2} = {x}^{4} \ 2 {x}^{2} + 2 = {x}^{2} \ {x}^{2} = - 2$
Пустое множество