Question

(5x-4)(3-5x)+12=0
Помогите

Answer 1

-25х²+35х-12+12=0
5х(7-5х)=0
х = 0
7 = 5х

х = 0; 7/5

Answer 2

(5x-4)(3-5x)+12=0

15x-25x²-12+20x+12=0

-25x²+35x=0

5x²-7x=0

x(5x-7)=0

x=0 или 5x-7=0

x=7/5

ответ: 0, 7/5