Question

$3^{(sqrt{-x})}$ = 9$sqrt{3}$

Answer 1

${3}^{ sqrt{ - x} } = 9 sqrt{3} \ odz \ - x geqslant 0 \ x leqslant 0\ {3}^{ sqrt{ - x} } = {3}^{2} times {3}^{ frac{1}{2} } \ {3}^{ sqrt{ - x} } = 3 {}^{ frac{5}{2} } \ \ sqrt{ - x} = frac{5}{2} \ - x = frac{25}{4} \ x = - frac{25}{4}$

Answer 2

Решение на фотографии