Question

12 задание с логорифмами

Answer 1

log₂₊ₓ 3 + 2/log₂ (2 + x) = 1

log₂₊ₓ 3 + 2 log₂₊ₓ 2 = 1

log₂₊ₓ 3 + log₂₊ₓ 4 = 1

log₂₊ₓ (3·4) = 1

(2 + x)¹ = 12

x = 10

Answer 2

$log_{2 + x}( 3 ) + frac{2}{ log_{2}(2 + x) } = 1 \ odz \ 2 + x > 0 : : : x > - 2 \ 2 + x≠1 : : : x ≠ - 1 \ log_{2}(2 + x) ≠ 0 \ 2 + x = 1 \ x ≠ - 1 \ x∈: ( - 2;- 1)(-1;+ ∞) \ log_{2 + x}(3) + frac{2}{ frac{1}{ log_{2 + x}(2) } } = 1 \ log_{2 + x}(3) + 2 log_{2 + x}(2) = 1 \ log_{2 + x}(3) + log_{2 + x}(4) = 1 \ log_{2 + x}(12) = 1 \ 2 + x = 12 \ x = 10$