Question

Помогите срочно! Нужны Б1, Б3, Б4

Answer 1

B1.

= |a-5| + |a-7| = a - 5 + 7 - a = 2

Ответ: 2

B3

y' = 8 - 8(x+12)⁷/(x+12)⁸ = 8 - 8/(x+12) = 0

1/(x+12) = 1

x+12 = 1

x = -11

y(-11,5) = -92 - ln((0,5)⁸) =-92 + 8ln2 ≈ -86,45

y(-11) = -88 - наименьшее

y(0) = -ln12⁸ ≈ -19,88

Ответ: -88

B4

$ODZ: x>0;xneq 1\ log_2x=y\ x=2^y\\ 3^y+2*2^{y*log_23}leq 3*2^{ylog_{2^y}9}\ 3^y+2*(2^{log_23}^y})leq 3*2^{log_29}\ 3^y+2*3^yleq 3*9\ 3^{y+1}leq 3^3\ y+1leq 3\ yleq 2\ log_2xleq 2\ xleq 4$

x∈(0;1) U (1; 4]

целые 2, 3, 4

Ответ: 3