Question

Сократите дробь y^2-4/y^2+3y+2

Answer 1

$frac{y^2-4}{y^2+3y+2}=frac{(y-2)(y+2)}{(y+1)(y+2)}=frac{y-2}{y+1}; ;\\\y^2+3y+2=0; ; to ; ; y_1=-2; ,; y_2=-1; ; (teorema; Vieta);to \\y^2+3y+2=(y-y_1)(y-y_2)=(y+2)(y+1)$