• Предмет: Математика
  • Автор: dimasrar21pc1xwx
  • Вопрос задан 8 лет назад

√(1+√2/1-√2)^2+2+(1-√2/1+√2)^2
Срочно пжпжпжпжпжпжп

Ответы

Ответ дал: zinaidazina
0

 (frac{1+sqrt{2}}{1-sqrt{2}} )^2+2+(frac{1-sqrt{2}}{1+sqrt{2}})^2=  (frac{(1+sqrt{2})^2}{(1-sqrt{2})(1+sqrt{2})})^2+2+(frac{(1-sqrt{2})(1-sqrt{2})}{(1-sqrt{2})(1+sqrt{2})})^2=  (frac{3+2sqrt{2}}{1-2})^2+2+(frac{3-2sqrt{2}}{1-2})^2=  (-(3+2sqrt{2} ))^2+2+(-(3-2sqrt{2} ))^2=  (3+2sqrt{2} )^2+2+(3-2sqrt{2} )^2= 9+12sqrt{2}+ 8+2  + 9-12sqrt{2}+ 8  =36

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