Question

log3 √7*(8x+1) = 6
Решить логарифмическое уравнение

Answer 1

$log_{3}( sqrt{7(8x + 1} ) = 6 \ frac{1}{2} times log_{3}(7(8x + 1)) = 6 \ log_{3}(7) + log_{3}(8x + 1) = 12 \ log_{3}(8x + 1) = 12 - log_{3}(7) \ 8x + 1 = frac{{3}^{12} }{7 } \ x = frac{(frac{{3}^{12} }{7 } - 1 )}{8} \ x = 66430$