Question

Помогите пожалуйста))))

Answer 1

$frac{4 times {18}^{n} }{ {3}^{2n - 1} times {2}^{n + 1} } = frac{ {2}^{2} times {9}^{n} times {2}^{n} }{{3}^{2n - 1} times {2}^{n + 1}} = \ \ = frac{ {3}^{2n} times {2}^{n + 2} }{{3}^{2n - 1} times {2}^{n + 1}} = {3}^{2n - (2n - 1)} times {2}^{n + 2 - (n + 1)} = \ \ = {3}^{1} times {2}^{1} = 6$


ОТВЕТ: Е