Question

(-x^2 y)^3 × (-x^4 y^2) упростите

Answer 1

$( - {x}^{2} y)^{3} times ( - {x}^{4} {y}^{2} ) = - {x}^{6} {y}^{6} times ( - {x}^{4} {y}^{2} ) = {x}^{10} {y}^{8}$