Question

(х-7)^2+3=(х-2)(х+2) подробное решение

Answer 1

${(x - 7)}^{2} + 3 = (x - 2)(x + 2) \ {x}^{2} - 2 times 7x + {7}^{2} + 3 = {x}^{2} - {2}^{2} \ {x}^{2} - 14x + 49 + 3 = {x}^{2} - 4 \ {x}^{2} - {x}^{2} - 14x + 49 + 3 + 4 = 0 \ - 14x + 56 = 0 \ - 14x = - 56 \ 14x = 56 \ x = frac{56}{14} = 4$
Ответ: 4

Answer 2

(х-7)²+3=(х-2)(х+2)
x²-14x+49+3=x²-4
-14x+49+3=-4
-14x+52=-4
-14x=-4-52
-14x=-56. |:(-14)
x=4
Ответ: 4