Question

Вычислите
1/(√7-√6)-3/(√6-√3)-4/(√7+√3)

Answer 1

$frac{1}{sqrt7-sqrt6}-frac{3}{sqrt6-sqrt3}-frac{4}{sqrt7+sqrt3}=frac{sqrt7+sqrt6}{7-6}-frac{3, (sqrt6+sqrt3)}{6-3}-frac{4, (sqrt7-sqrt3)}{7-3}=\\=frac{sqrt7+sqrt6}{1}-frac{3sqrt6+3sqrt3}{3}-frac{4sqrt7-4sqrt3}{4}=frac{12sqrt7+12sqrt6-12sqrt6-12sqrt3-12sqrt7+12sqrt3}{12}=\\=frac{0}{12}=0$

Answer 2

Большое спасибо