Question

помогите с решением

Answer 1

a₆ = (-1)⁶ sin(6π/18) = sin(π/3) = √3/2

a₂₄ = (-1)²⁴ sin(24π/18) = sin(4π/3) = sin(π + π/3) = -sin(π/3) = -√3/2

a₆ + a₂₄ = √3/2 - √3/2 = 0

Ответ: 1) 0.

Answer 2

an=(-1)ⁿsinπn/18
a6+a24=
sin6π/18+sin24π/18=sinπ/3+sin4π/3=
√3/2+sin(π+π/3)=√3/2-sinπ/3=
√3/2-√3/2=0