Question

Выполните разложение многочленов :
(n-3m)(3m+n)
(2a-3b)(3b+2a)
(8c+9d)(9d-8c)

Разложите на множители :
9m^2-16n^2
64p^2-81q^3
9-b^2c^2
4a^2b^2-1

Answer 1

$(n - 3m)(3m + n) = {n}^{2} - {(3m)}^{2} = {n}^{2} - 9 {m}^{2} \ \ (2a - 3b)(3b + 2a) = {(2a)}^{2} - {(3b)}^{2} = 4 {a}^{2} - 9 {b}^{2} \ \ (8c + 9d)(9d - 8c) = {(9d)}^{2} - {(8c)}^{2} = 81 {d}^{2} - 64 {c}^{2} \ \ \ 9 {m}^{2} - 16 {n}^{2} = {(3m)}^{2} - {(4n)}^{2} = (3m - 4n)(3m + 4n) \ \ 64 {p}^{2} - 81 {q}^{2} = {(8p)}^{2} - {(9q)}^{2} = (8p - 9q)(8p + 9q) \ \ 9 - {b}^{2} {c}^{2} = {3}^{2} - {(bc)}^{2} = (3 - bc)(3 + bc) \ \ 4 {a}^{2} {b}^{2} - 1 = {(2ab)}^{2} - {1}^{2} = (2ab - 1)(2ab + 1)$

Answer 2

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