Question

ПОМОГИТЕ
!!!Заранее спасибо!!!

Answer 1

7) а(4-с) - (4-с)=(4-с)(а-1)
8)
${x}^{3} ( {x}^{4} - 1) + 4( {x}^{4} - 1) = ( {x}^{4} - 1)( {x}^{3} + 4) = ( {x}^{2} - 1)( {x}^{2} + 1)( {x}^{3} + 4)=( x- 1)(x+1)( {x}^{2} + 1)( {x}^{3} + 4)$
9)
$3 {a}^{2} (2b - 1) + a(2b - 1) = (2b - 1)(3 {a}^{2} + а)=а(3а+1)(2b-1)$

Answer 2

не поняла

Answer 3

Не Вы, а решатель

Answer 4

аааа понятно

Answer 5

спасибо

Answer 6

спасибо

Answer 7

$7) : : 4a - ac - 4 + c = (4a - 4) - (ac - c) = 4(a - 1) - c(a - 1) = (a - 1)(4 - c)$
$8) : : {x}^{7} - {x}^{3} + 4 {x}^{4} - 4 = ( {x}^{7} - {x}^{3} ) + (4 {x}^{4} - 4) = {x}^{3} ( {x}^{4} - 1) + 4( {x}^{4} - 1) = ( {x}^{3} + 4)( {x}^{4} - 1) =( {x}^{3} + 4)( {x}^{2} - 1)( {x}^{2} + 1)$
$9) : : 6 {a}^{2} b - 3 {a}^{2} + 2ab - a = (6 {a}^{2} b - 3 {a}^{2} ) + (2ab - a) = 3 {a}^{2} (2b - 1) + a(2b - 1) = (3 {a}^{2} + a)(2b - 1) = a(3a + 1)(2b - 1)$

Answer 8

спасибо вам