Question

(z+x+3)^2=(z+x)^2+2*(z+x)*3+3^2=Раскройте скобки=

Answer 1

${(z + x + 3)}^{2} = {(z + x)}^{2} + 2 times (z + x) times 3 + {3}^{2} = {z}^{2} + 2zx + {x}^{2} + 6z + 6x + 9$