Question

Помогите пожалуйста!!!

Answer 1

$frac{3}{ {x}^{2} - 1} - frac{1}{2x + 2} = frac{1}{4} \ frac{3}{(x - 1)( x + 1)} - frac{1}{2(x + 1)} - frac{1}{4} = 0 \ frac{12}{4(x - 1)(x + 1)} - frac{2(x - 1)}{4(x - 1)(x + 1)} - frac{(x - 1)(x + 1)}{4(x - 1)(x + 1)} = 0 \ frac{12 - 2(x - 1) - (x - 1)(x + 1)}{4(x - 1)(x + 1)} = 0 \ frac{12 - 2x + 2 - {x}^{2} + 1}{4(x - 1)(x + 1)} = 0 \ frac{ - {x}^{2} - 2x + 15 }{4(x - 1)(x + 1)} = 0 \ - {x}^{2} - 2x + 15 = 0 \ {x}^{2} + 2x - 15 = 0 \ d = {b}^{2} - 4ac = 4 - 4 times ( - 15) = 64 \ x1 = frac{ - 2 + 8}{2} = frac{6}{2} = 3 \ x2 = frac{ - 2 - 8}{2} = frac{ - 10}{2} = - 5$
Ответ: -5; 3.

Answer 2

Где?

Answer 3

3 строчка

Answer 4

Приводим к общему знаменателю

Answer 5

понял

Answer 6

спасибо