Question

Геометрическая прогрессия

Answer 1

1)
$cn = c1 times {q}^{n - 1} \ c3 = c1 times {q}^{2} \ c1 = frac{c3}{ {q}^{2} } = frac{144}{16} = 9$
Ответ: 9.

2)
$cn = c1 times {q}^{n - 1} \ c2 = c1 times q = 3 times 3 = 9 \ c3 = c1 times {q}^{2} = 3 times 9 = 27 \ c4 = c1 times {q}^{3} = 3 times 27 = 81 \ c5 = c1 times {q}^{4} = 3 times 81 = 243$
Ответ: 3; 9; 27; 81; 243