Question

решите пожалуйста)))

Answer 1

$frac{x^{12}*x^{3}}{x^{13}}=frac{x^{12+3}}{x^{13}}=x^{15-13}=x^{2} \\2^{2} =4\\\frac{x^{2}y^{3}}{4} :frac{20x}{y}=frac{x^{2}y^{3}}{4}*frac{y}{20x}=frac{x*y^{4}}{80}\\frac{-1*3^{4}}{80}=-frac{81}{80}=-1frac{1}{80}=-1,0125\\\(a^{2})^{3}:a^{5}=a^{6}:a^{5}=a^{6-5}=a, a=frac{1}{2}\\\frac{2^{4}}{3^{3}} :frac{2^{6}}{3^{5}} =frac{2^{4}}{3^{3}}*frac{3^{5}}{2^{6}}=frac{3^{2}}{2^{2}}=frac{9}{4}=2,25$