Question

{x+4y/9 - x-2y/3 = 0
{x+7y/4 + x+y/6 = 4

Answer 1

$frac{x + 4y}{9} - frac{x - 2y}{3} = 0 \ frac{x + 7y}{4} + frac{x + y}{6} = 4 \ \ x + 4y - 3(x - 2y) = 0 \ 3(x + 7y) + 2(x + y) = 48 \ \ x + 4y - 3x + 6y = 0 \ 3x + 21y + 2x + 2y = 48 \ \ - 2x + 10y = 0 \ 5x + 23y = 48 \ \ 2x = 10y \ 5x + 23y = 48 \ \ x = 5y \ 5x + 23y = 48 \ \ x = 5y \ 25y + 23y = 48 \ \ x = 5y \ 48y = 48 \ \ y = 1 \ x = 5y \ \ y = 1 \ x = 5$
Ответ: (5; 1)