Question

СРОЧНО помогите с решением

Answer 1

$y=3^{sqrt{x+5}}$

$y^2-10y+9=0$

$y=1; y=9$

$3^{sqrt{x+5}}=3^0; 3^{sqrt{x+5}}=3^2$

$sqrt{x+5}=0; sqrt{x+5}=2$

$x=-5; x=-1$

$-5-1=-6$

Answer 2

$3^{2sqrt{x+5}}-10cdot 3^{sqrt{x+5}}+9=0; ,; ; ; ODZ:; ; x+5geq 0; ,; ; xgeq -5\\3^{2sqrt{x+5}}=(3^{sqrt{x+5}})^2\\t=3^{sqrt{x+5}}>0; ,; ; t^2-10t+9=0; ,\\t_1=1; ,; t_2=9; ; (teorema; Vieta)\\3^{sqrt{x+5}}=1; ,; ; 3^{sqrt{x+5}}=3^0; to ; sqrt{x+5}=0; ,; x+5=0; ,; x=-5\\3^{x+5}=9; ,; 3^{sqrt{x+5}}=3^2; to ; sqrt{x+5}=2; ,; x+5=4; ,; x=-1\\Otvet:; ; x=-5; ,; x=-1.$