Question

Геометрическая прогрессия

Answer 1

$cn = c1 times {q}^{n - 1} \ c1 = 2 \ c2 = c1 times q = 2 times 3 = 6 \ c3 = c1 times {q}^{2} = 2 times {3}^{2} = 2 times 9 = 18 \ c4 = c1 times {q}^{3} = 2 times {3}^{3} = 2 times 27 = 54 \ c5 = c1 times {q}^{4} = 2 times {3}^{4} = 2 times 81 = 162$
Ответ: 2, 6, 18, 54, 162