Question

23 и 24 срочно!!!!!!!!!

Answer 1

$frac{(sqrt{2+sqrt{3}}+sqrt{2-sqrt{3}})^2}{(2+sqrt{3})-(2-sqrt{3})} =\\ =frac{2+sqrt{3}+2-sqrt{3}+2sqrt{(2-sqrt{3})(2+sqrt{3})}}{2sqrt{3}} =\\ =frac{4+2sqrt{4-3}}{2sqrt{3}} =frac{6}{2sqrt{3}} =sqrt{3}$

24.

$frac{3(sqrt{7}+2)}{7-4} +frac{2(sqrt{7}+3)}{7-9} =\\ =sqrt{7}+2-(sqrt{7}+3) = 2 - 3 = -1$